Optimal. Leaf size=270 \[ -\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{x}+\frac {g j m \log \left (-\frac {e x}{d}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{i}-\frac {g j m \log \left (\frac {e (i+j x)}{e i-d j}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{i}+\frac {b e n \log \left (-\frac {j x}{i}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{d}-\frac {b e n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{d}-\frac {b g j m n \text {Li}_2\left (-\frac {j (d+e x)}{e i-d j}\right )}{i}+\frac {b g j m n \text {Li}_2\left (\frac {e x}{d}+1\right )}{i}-\frac {b e g m n \text {Li}_2\left (\frac {e (i+j x)}{e i-d j}\right )}{d}+\frac {b e g m n \text {Li}_2\left (\frac {j x}{i}+1\right )}{d} \]
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Rubi [A] time = 0.33, antiderivative size = 270, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 9, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.281, Rules used = {2439, 36, 29, 31, 2416, 2394, 2315, 2393, 2391} \[ -\frac {b g j m n \text {PolyLog}\left (2,-\frac {j (d+e x)}{e i-d j}\right )}{i}+\frac {b g j m n \text {PolyLog}\left (2,\frac {e x}{d}+1\right )}{i}-\frac {b e g m n \text {PolyLog}\left (2,\frac {e (i+j x)}{e i-d j}\right )}{d}+\frac {b e g m n \text {PolyLog}\left (2,\frac {j x}{i}+1\right )}{d}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{x}+\frac {g j m \log \left (-\frac {e x}{d}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{i}-\frac {g j m \log \left (\frac {e (i+j x)}{e i-d j}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{i}+\frac {b e n \log \left (-\frac {j x}{i}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{d}-\frac {b e n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{d} \]
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 2315
Rule 2391
Rule 2393
Rule 2394
Rule 2416
Rule 2439
Rubi steps
\begin {align*} \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x^2} \, dx &=-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}+(g j m) \int \frac {a+b \log \left (c (d+e x)^n\right )}{x (391+j x)} \, dx+(b e n) \int \frac {f+g \log \left (h (391+j x)^m\right )}{x (d+e x)} \, dx\\ &=-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}+(g j m) \int \left (\frac {a+b \log \left (c (d+e x)^n\right )}{391 x}-\frac {j \left (a+b \log \left (c (d+e x)^n\right )\right )}{391 (391+j x)}\right ) \, dx+(b e n) \int \left (\frac {f+g \log \left (h (391+j x)^m\right )}{d x}-\frac {e \left (f+g \log \left (h (391+j x)^m\right )\right )}{d (d+e x)}\right ) \, dx\\ &=-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}+\frac {1}{391} (g j m) \int \frac {a+b \log \left (c (d+e x)^n\right )}{x} \, dx-\frac {1}{391} \left (g j^2 m\right ) \int \frac {a+b \log \left (c (d+e x)^n\right )}{391+j x} \, dx+\frac {(b e n) \int \frac {f+g \log \left (h (391+j x)^m\right )}{x} \, dx}{d}-\frac {\left (b e^2 n\right ) \int \frac {f+g \log \left (h (391+j x)^m\right )}{d+e x} \, dx}{d}\\ &=\frac {1}{391} g j m \log \left (-\frac {e x}{d}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{391} g j m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (391+j x)}{391 e-d j}\right )+\frac {b e n \log \left (-\frac {j x}{391}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {b e n \log \left (-\frac {j (d+e x)}{391 e-d j}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}-\frac {1}{391} (b e g j m n) \int \frac {\log \left (-\frac {e x}{d}\right )}{d+e x} \, dx+\frac {1}{391} (b e g j m n) \int \frac {\log \left (\frac {e (391+j x)}{391 e-d j}\right )}{d+e x} \, dx-\frac {(b e g j m n) \int \frac {\log \left (-\frac {j x}{391}\right )}{391+j x} \, dx}{d}+\frac {(b e g j m n) \int \frac {\log \left (\frac {j (d+e x)}{-391 e+d j}\right )}{391+j x} \, dx}{d}\\ &=\frac {1}{391} g j m \log \left (-\frac {e x}{d}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{391} g j m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (391+j x)}{391 e-d j}\right )+\frac {b e n \log \left (-\frac {j x}{391}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {b e n \log \left (-\frac {j (d+e x)}{391 e-d j}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}+\frac {1}{391} b g j m n \text {Li}_2\left (1+\frac {e x}{d}\right )+\frac {b e g m n \text {Li}_2\left (1+\frac {j x}{391}\right )}{d}+\frac {(b e g m n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {e x}{-391 e+d j}\right )}{x} \, dx,x,391+j x\right )}{d}+\frac {1}{391} (b g j m n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {j x}{391 e-d j}\right )}{x} \, dx,x,d+e x\right )\\ &=\frac {1}{391} g j m \log \left (-\frac {e x}{d}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{391} g j m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (391+j x)}{391 e-d j}\right )+\frac {b e n \log \left (-\frac {j x}{391}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {b e n \log \left (-\frac {j (d+e x)}{391 e-d j}\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{d}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (391+j x)^m\right )\right )}{x}-\frac {1}{391} b g j m n \text {Li}_2\left (-\frac {j (d+e x)}{391 e-d j}\right )+\frac {1}{391} b g j m n \text {Li}_2\left (1+\frac {e x}{d}\right )+\frac {b e g m n \text {Li}_2\left (1+\frac {j x}{391}\right )}{d}-\frac {b e g m n \text {Li}_2\left (\frac {e (391+j x)}{391 e-d j}\right )}{d}\\ \end {align*}
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Mathematica [A] time = 0.23, size = 476, normalized size = 1.76 \[ -\frac {a d f i+a d g i \log \left (h (i+j x)^m\right )-a d g j m x \log \left (-\frac {j x}{i}\right )+a d g j m x \log (i+j x)+b d f i \log \left (c (d+e x)^n\right )+b d g i \log \left (c (d+e x)^n\right ) \log \left (h (i+j x)^m\right )-b d g j m x \log \left (-\frac {j x}{i}\right ) \log \left (c (d+e x)^n\right )+b d g j m x \log (i+j x) \log \left (c (d+e x)^n\right )+b e f i n x \log (d+e x)+b e g i n x \log (d+e x) \log \left (h (i+j x)^m\right )+b e g i m n x \text {Li}_2\left (\frac {e (i+j x)}{e i-d j}\right )+b d g j m n x \text {Li}_2\left (\frac {j (d+e x)}{d j-e i}\right )-b e g i m n x \log (d+e x) \log (i+j x)+b e g i m n x \log (i+j x) \log \left (\frac {j (d+e x)}{d j-e i}\right )+b d g j m n x \log (d+e x) \log \left (-\frac {j x}{i}\right )-b d g j m n x \log (d+e x) \log (i+j x)+b d g j m n x \log (d+e x) \log \left (\frac {e (i+j x)}{e i-d j}\right )-b d g j m n x \text {Li}_2\left (\frac {e x}{d}+1\right )-b d g j m n x \log \left (-\frac {e x}{d}\right ) \log (d+e x)-b e f i n x \log (x)-b e g i n x \log (x) \log \left (h (i+j x)^m\right )+b e g i m n x \text {Li}_2\left (-\frac {j x}{i}\right )+b e g i m n x \log (x) \log \left (\frac {j x}{i}+1\right )}{d i x} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b f \log \left ({\left (e x + d\right )}^{n} c\right ) + a f + {\left (b g \log \left ({\left (e x + d\right )}^{n} c\right ) + a g\right )} \log \left ({\left (j x + i\right )}^{m} h\right )}{x^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 2.60, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \ln \left (c \left (e x +d \right )^{n}\right )+a \right ) \left (g \ln \left (h \left (j x +i \right )^{m}\right )+f \right )}{x^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -b e f n {\left (\frac {\log \left (e x + d\right )}{d} - \frac {\log \relax (x)}{d}\right )} - a g j m {\left (\frac {\log \left (j x + i\right )}{i} - \frac {\log \relax (x)}{i}\right )} + b g \int \frac {{\left (\log \left ({\left (e x + d\right )}^{n}\right ) + \log \relax (c)\right )} \log \left ({\left (j x + i\right )}^{m}\right ) + \log \left ({\left (e x + d\right )}^{n}\right ) \log \relax (h) + \log \relax (c) \log \relax (h)}{x^{2}}\,{d x} - \frac {b f \log \left ({\left (e x + d\right )}^{n} c\right )}{x} - \frac {a g \log \left ({\left (j x + i\right )}^{m} h\right )}{x} - \frac {a f}{x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )\,\left (f+g\,\ln \left (h\,{\left (i+j\,x\right )}^m\right )\right )}{x^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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